Does anyone know how to do 1 and 2? i suck at trigonometry.
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The graph is a straight line graph with a slope of -1/2
Equation of a line in point-slope form
The equation of a line in point slope form is expressed as:
y - y₁ = m(x - x₁)
Given the following parameters
Point = (-2, 3)
Slope = -1/2
Substitute the given parameters into the formula
y-3 = -1/2(x-(-2))
y-3 = -1/2(x+2)
Write in slope-intercept form
2(y-3) = -(x+2)
2y-2(3) = -x -2
2y - 6 = -x -2
2y = -x + 4
y = -1/2x + 2
The graph of the equation is as shown below
Learn more on equation of a line here: brainly.com/question/18831322
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