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mario62 [17]
3 years ago
14

Construction crew is using heavy equipment to dig a hole in which the foundation of a house will be built. The whole will be in

the shape of a right rectangular prism with dimensions of 4 feet in depth, 100 feet long, and 50 feet wide. The soil will be removed using a truck that can hold a maximum of 40,000 pounds. The soil weighs 90 pounds per cubic foot. What is the least number of truckloads needed to remove all of the soil ?
Mathematics
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

5

Step-by-step explanation:

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A committee of 4 boys is selected from 10 boys?
klio [65]

Answer:

I don't know about this thing

8 0
3 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
Question 27 <br> Find the length of the hypotenuse. Leave answer in simplest radical form.
skelet666 [1.2K]

Use SOHCAHTOA.  Since we are looking for the hypotenuse, you must use sine or cosine.  Since, we are given the adjacent side, use cosine.

cosx=a/h

cos45=8/h

√2/2=8/h

<em>*Cross multiply*</em>

h√2=16

<em>*Divide both sides by √2*</em>

h=16/√2

<em>*Multiply by √2/√2*</em>

h=(16√2)/2

<em>*Simplify the fraction*</em>

h=8√2

Hope this helps!!

6 0
3 years ago
PLEASE HELP ASAP!!
sergeinik [125]
There is a strong, negative relationship between outside temperature and snow shovel sales. As x increases, y decreases.
6 0
3 years ago
A student's tuition was $5530. A loan was obtained for 4/7 of the tuition. How much was the loan?
Sophie [7]
Multiply the two numbers to find the amount of the loan.

5530/1* 4/7= 22120/7= 3160

Final answer: $3,160
5 0
3 years ago
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