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olga2289 [7]
3 years ago
9

HELP?!?

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0

Answer:

1.  5 x 47    show tree of 5  x  47 and then stop both are pf

2.  2^2 × 5 × 23   show tree of  10 x 46 and then 2 x 5 (under10) and 2x23 (under 46) and then stop  2,2,5,23 are all pf

3. 2 x 3 x 97   show tree 3 x 194 and 2 x 97 and circle pf 2,3,97

4.  3^3 x 11  show tree of 3 x 99  then 3  x 33 then 3 x 11 to show 3,3,3,11 as pf

5. 3 x 7 x 37 show tree as  777/7  = 111/37 = 3 to show 3,7,37 as pf

6. 2^4 x 3 x 13 show tree as 2 x 312  2 x 156  2 x 78  2 x 39  3 x 13 to show 2,2,2,2,3,13 all as pf

Step-by-step explanation:

spin [16.1K]3 years ago
6 0

Step-by-step explanation:

hear is answer in attachment

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8 0
3 years ago
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Anyone please help me pleaseeee
lora16 [44]

R = { (x,y): 3x-y=0 }

The condition is 3x=y so that's not going to be any of these things.

R is reflexive if (x,x)∈R for all x.   Let's check.

3x - y = 3x - x = 2x ≠ 0  necessarily.   NOT REFLEXIVE

R is symmetric if (x,y)∈R → (y,x)∈R.   Let's check.

(x,y)∈R  so

3x-y = 0

y  = 3x

Is  (y,x)∈R.  That would be true if 3y-x=0

3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC

R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R.   Let's check.

3x-y = 0  so y=3x

3y-z = 0 so z=3y = 9x

3x - z = 3x - 9x = -6x ≠ 0 necessarily   NOT TRANSITIVE

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3 years ago
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