Answer:
24.36m²
Step-by-step explanation:
area = ½×(8.9+2.7)×4.2= ½×48.72=24.36m²
1. Let the sides of a triangle be a, b and c.
Assume c is the largest side.
The maximum angle measure in an acute triangle can be 90°. In such a case we would have
Now forget about side c, and open the angle between a and b just a little bit. Now clearly
is larger that
because the "new c" is larger than the old one.
2. So for 3 numbers to be the lengths of the sides of an acute triangle, the sum of the squares of the 2 smaller numbers must be at most equal to the square of the largest number but not more.
Check:
A. 4^2+5^2=16+25=41<49
B. 5^2+7^2=25+49=74>64
C. 6^2+7^2=36+49=85<100
D. 7^2+9^2=49+81=130<144
3. Correct answer: only B
What are the questions? Lol
Answer:
the second day
Step-by-step explanation:
4(d + 2) - 2d = 3(2 + d)
4d + 8 -2d = 6 + 3d
2d + 8 = 3d + 6
-6 -6
2d + 2 = 3d
-2d -2d
2 = d
to check your answer:
4(2 + 2) - 2(2) = 3(2 + 2)
4(4) - 4 = 3(4)
16 - 4 = 12
12 = 12
Answer:
Tanks of 15.3081 gallons and larger are considered too large.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
How large does a tank have to be to be considered too large
largest 2%, so at least the 98th percentile.
The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.
Tanks of 15.3081 gallons and larger are considered too large.