Can someone do 11-12?
1 answer:
You might be interested in
To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
For this case we must simplify the following expression:
We must add similar terms taking into account that:
- Equal signs are added and the same sign is placed.
- Different signs are subtracted and the major sign is placed.
Thus, the simplified expression is:
Answer: