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Zarrin [17]
3 years ago
14

Can someone please help!!!!!!!

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

The graph is attached in the figure below.

Step-by-step explanation:

To graph a point we perform the following steps.

  • Consider point J(-5,2.5)
  • Here x = -5, and y = 2.5
  • Find -5 in x axis and 2.5 in y-axis. the point where both meet is the point for J on graph.

All other points are also drawn in the graph following the above steps.

The graph is attached in the figure below.

Keywords: Graph

Learn more about Graphs at:

  • brainly.com/question/10541435
  • brainly.com/question/3126500
  • brainly.com/question/11150876
  • brainly.com/question/2334270

#learnwithBrainly

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What is the measure of E?
IceJOKER [234]
You can get E real quick
how? you know that D is 90 and f is given 66 and you know that D+E+F=180 so E=180-(90+66) which gives us 24
6 0
3 years ago
Write the equation in slope-intercept form then change it to standard form with integer coefficients.
SCORPION-xisa [38]

Answer:

1. Slope-intercept form:   y = 2x - 4

Standard form:   2x - y = 4

2. Slope-intercept form:  y = \dfrac12x - 1

Standard form:             x - 2y = 2

3. Slope-intercept form:   y = \dfrac45x + \dfrac{21}{5}

Standard form:            4x -5y = - 21

Step-by-step explanation:

Slope intercept form:   y = mx + b

where:

  • y = y-coordinate
  • m = slope
  • x = x-coordinate
  • b = y-intercept

Standard form:  Ax + By = C

\textsf{1.  as} \ m=2: \ \ y = 2x + b

   \textsf{at} \  (6, 8): \ \ 8 = 2(6) + b

   \implies b = -4

Slope-intercept form:   y = 2x - 4

Standard form:   2x - y = 4

\textsf{2.  as} \  \ m = \dfrac12: \ \ y = \dfrac12x + b

    \textsf{at} \  (4, 1): \ \ 1 = \dfrac12(4) + b

    \implies b = -1

Slope-intercept form:  y = \dfrac12x - 1

Standard form:             x - 2y = 2

\textsf{3.  as} \  \ m = \dfrac45: \ \ y = \dfrac45x + b

   \textsf{at} \  (1,5): \ \ 5 = \dfrac45(1) + b

   \implies b = \dfrac{21}{5}

Slope-intercept form:   y = \dfrac45x + \dfrac{21}{5}

Standard form:            4x -5y = - 21

7 0
2 years ago
Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form
Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

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4 0
3 years ago
Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the
mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ ,  μ₀ + σ]   contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ ,  μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ]   ⇒  [ 78 - (0,5)*8 , 78 + (0,5)*8 ]  ⇒[ 74 , 82]

[ μ₀ - σ ,  μ₀ + σ]  ⇒ [ 78 - 8 , 78 +8 ]   ⇒  [ 70 , 86 ]

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]  ⇒ [ 78 - 12 , 78 + 12 ]  ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]    ⇒  [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7  = 0,3 %

Only 0,3 % of population is out of   μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

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3 years ago
Expand (x – 4)^5 using the Binomial Theorem and Pascal’s triangle
worty [1.4K]

5th \: row = 1 \:  \: \:  5 \: \:   \: 10 \:  \:  \: 10 \:  \: \:  5 \: \:   \: 1

(x - 4) {}^{5}  = x {}^{5}  + 5x {}^{4} ( - 4) {}^{1}  + 10x {}^{3} ( - 4) {}^{2}  + 10x {}^{2} ( - 4) {}^{3}  + 5x( - 4) {}^{4}  + ( - 4) {}^{5}

(x - 4)  {}^{5}  = x {}^{5}  - 20x {}^{4}  + 160x {}^{3}  - 640x {}^{2}  + 1280x  - 1024

7 0
2 years ago
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