Question

I need help with 9-14 pleasee

Answer 1

Short answer P(at least 1 king) = 0.341158
Comment
The easy way to do this is to figure out what the Combinatorics are for no kings. Subtract that result from 1.

Total number of ways of drawing 5 cards - any order.
P(any 5 cards) = 52 C 5
P(any 5 cards) = $\frac{52 * 51 * 50 * 49 * 48}{5 * 4 * 3 * 2 * 1}$
P(any 5 cards) = 26 * 51 * 5 * 8 * 49 = 2598960 Note: I did this by canceling 5!.

P(no kings) = 48 C 5 

The probability of getting no kings = (48 C 5) / 52 C 5 = 0.65884

The probability of getting at least 1 king = 1 - 0.65884 = 0.34115