Question

Find the zeros of the quadratic equation- v(5v-7)=0

Answer 1

Answer:

Step-by-step explanation:

v(5v-7)=0

We multiply parentheses

5v^2-7v=0

a = 5; b = -7; c = 0;

Δ = b2-4ac

Δ = -72-4·5·0

Δ = 49

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

v1 = −b−√Δ/2a

v2 = -b+√Δ/2a

√Δ = √49 = 7

v1 = -(−7)−7/2*5 = 0/10 = 0

v2 = -(−7)+7/2*5 = 14/10 =  1+2/5