The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as

.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:



Now we can use the law of sines to find the distance

between Paul and Jose:



Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:

We can conclude that Jose is 33.9m from the base of the tree.
Answer:
from this table we can tell Y is always 10 times bigger then X so we just have to multiply it again by ten so the answers are
300
500
700
Answer:
I'm late but the answer to the question on the left is 21 and the answer to the question on the right is 3.
Step-by-step explanation:
Remember that you have to complete the equations in order of PEMDAS.
19-3×4÷(-6)
For this equation, you would do 3×4 first (which equals 12) then divide that by -6 (Which equals - 2) and finally you would subtract that from 19. 19 - (-2)= 21
6(-8) / -12 - 1
For this equation you would do 6(-8) first (which equals -48) then divide that by -12 (which equals 4) and finally subtract 1 from that 4. 4-1=3
Answer is D
sum of constants = 8 + 4 = 12
sum of coefficients = 7 + 3 = 10
12 > 10
65 yards because of a2+b2=c2