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White raven [17]

3 years ago

14

3 more than twice a number is 15 what is the number

2 answers:

Mnenie [13.5K]3 years ago

6 0

2x+3=15

2(6)+3=15
12+3=15 ✅

vredina [299]3 years ago

4 0

The number is 6 for this

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If the area of a rectangle is

Zielflug [23.3K]

(5x+3) is the width, its factors form is (5x+3)(3x-5)

5 0

3 years ago

The volume of a cone is 3πx3 cubic units and its height is x units. Which expression represents the radius of the cone’s base, i

dalvyx [7]

Answer:

<em>r=3x</em>

Step-by-step explanation:

<u>The Volume of a Cone</u>

The volume of a cone of radius r and height h is:

$\displaystyle V=\frac{1}{3}\pi hr^2$

We are given the volume of a cone is

$V=3\pi x^3$

Equating:

$\displaystyle \frac{1}{3}\pi hr^2=3\pi x^3$

Multiplying by 3:

$\pi hr^2=9\pi x^3$

Simplifying by pi:

$hr^2=9 x^3$

Since h=x:

$xr^2=9 x^3$

Dividing by x:

$r^2=9 x^2$

Taking square roots:

$r=\sqrt{9 x^2}=3x$

Thus: r=3x

5 0

3 years ago

Read 2 more answers

What is the nth term of the sequence -2 -8 -18 -32 -50

andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
$T_{n} = an^{2} +bn +c$

To find the value of a we just divide second difference ( -4 ) by 2:

$a = \frac{-4}{2}= -2$

Now we have:

$T_{n}= -2n^{2} +bn+c$

Substitute $n_{1}$ and $n_{2}$ into the equation above:

$T_{1} = -2(1)^{2} +b(1) +c$

$T_{2} = -2(2)^{2} +b(2)+c$

Since $T_{1}$ = -2 and $T_{2}$ = -8 , after simplification we have:

$b +c =0$
$2b+c=0$

The solution of this system is:

b=0, c =0

The general term is :

$T_{n} = -2n^{2}$

6 0

2 years ago

Fraction that is less than 5/6 and has a denominator of 8

Evgesh-ka [11]

See 5/6 is obviously more than 1/2 so 4/8 works
also 3/8 or 2/8 or 1/8

if you want all fractions then
5/6=x/8
times 24 both sides
20=3x
divide 3
6 and 2/3=x
basically x/8 such that x<6 and 2/3

examples
6/8
5/8
4/8
3/8
2/8
1/8
I would use the odd ones since the even ones simplify to non-eight denomenators

7 0

3 years ago

The model represents x2 – 9x + 14. An algebra tile configuration showing only the Product spot. 24 tiles are in the Product spot

klio [65]

I didn't get all the part with the tiles, but here's the general answer:

given a polynomial

$p(x)=ax^2+bx+c$

we have that $x-k$ is a factor of $p(x)$ if and only if k is a root of $p(x)$ , i.e. if

$p(k)=ak^2+bk+c=0$

So, given the polynomial

$p(x)=x^2-9x+14$

We can check if $x-9$ is a factor by evaluating $p(9)$ :

$p(9)=81-81+14=14\neq 0$

So, $x-9$ is not a factor.

Similarly, we can evaluate $p(2),\ p(-5),\ p(-7)$ to check if $x-2,\ x+5,\ x+7$ are factors:

$p(2)=4-18+14=0,\quad p(-5)=25+45+14=84\neq 0,\quad p(-7)=49+63+14=126 \neq 0$

So, only $x-2$ is a factor of $x^2-9x+14$

4 0

4 years ago

Read 2 more answers