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liberstina [14]
3 years ago
3

Proving the Parallelogram Side Theorem

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

i need little more

Step-by-step explanation:

jolli1 [7]3 years ago
3 0

Answer:

A parallelogram is a quadrilateral that has two parallel and equal pairs of opposite sides.    

From the given diagram,

Given: AD = BC and AD || BC, then:

i. AB = DC (both pairs of opposite sides of a parallelogram are congruent)

ii. <ADC = < BCD and < DAB = < CBA

thus, AD || BC and AB || DC (both pairs of opposite sides of a parallelogram are parallel)

iii. < BAC = < DCA (alternate angle property)

iv. Join BD, line AC  and BC are the diagonals of the quadrilateral which bisect each other. The two diagonals are at a right angle to each other.

v. <ADC + < BCD + < DAB + < CBA =   (sum of angles in a quadrilateral equals 4 right angles)

Therefore, ABCD is a parallelogram.

Step-by-step explanation:

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