the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:11+2x
Step-by-step explanation:
(10-7-x)+(4+4+3x)
3-x+8+3x
3+8+3x-x
11+2x
Answer:
dfffffffff
Step-by-step explanation:
xcdsw23456iu76
If u can help with this question, the options for both x' s are -8,-7,-6,-5,-4,-3,-2,-1,1,2,3,4,5,6,7,8
Simora [160]
1x + 1y = 100....multiply by -3/8
3/8x + 7/8y = 2000
no need to multiply the other equation by anything....the x's will cancel because one will be -3/8x and one will be 3/8x
Answer:
1 is your answer for p
Step-by-step explanation:
First simplify. Divide 6 with 2
-6/2 = -3
10p + 5 = 18p - 3
Next, isolate the p. Note the equal sign. What you do to one side, you do to the other. Subtract 5 and 18p from both sides
10p (-18p) + 5 (-5) = 18p (-18p) - 3 (-5)
10p - 18p = -3 - 5
Simplify. Combine like terms
-8p = -8
Isolate the p. Divide -8 from both sides
(-8p)/-8 = (-8)/-8
p = -8/-8
p = 1
---------------------------------------------------------------------------------------------------------
<em>~Senpai</em>
