To construct a circle that circumscribes to a triangle, you would have to construct a circle that where all vertices of the triangle are on the circle. To do this you would have to construct the perpendicular bisectors of each side with your compass and straight edge. Comment on this answer if you are unsure of how to construct a perpendicular bisect (it's a long fundamental process to describe, and I wouldn't want to lecture you one something you already know). Once you have done so, set your compass point on the point where all perpendicular bisectors intersect (they should intersect in ONE point, if not you will have to redo it). Set your other compass lead on one of the vertices and spin away! If you have done this correctly, you should hit all three vertices when spinning your compass. Hope this helps!
Fun fact: the point where all perpendicular bisectors intersect is called the circumcenter
the volume of the cone would be 2.36 I hope this helps ❤️
X:2+(105-275:11):4=28
X:2+(105-25):4=28
X:2+80:4=28
X:2+20=28
X:2=28-20
X:2=8
X=8×2
X=16
Answer:
y= (-7/16)
Step-by-step explanation:
Multiply (3/4)(1/4)= (3/16)
y= (3/16)-(5/8)
y= (-7/16)
I hope this is right, im not 100% sure
Answer:
Part 1) The length of the diagonal of the outside square is 9.9 units
Part 2) The length of the diagonal of the inside square is 7.1 units
Step-by-step explanation:
step 1
Find the length of the outside square
Let
x -----> the length of the outside square
c ----> the length of the inside square
we know that
step 2
Find the length of the inside square
Applying the Pythagoras Theorem
substitute
step 3
Find the length of the diagonal of the outside square
To find the diagonal Apply the Pythagoras Theorem
Let
D -----> the length of the diagonal of the outside square
step 4
Find the length of the diagonal of the inside square
To find the diagonal Apply the Pythagoras Theorem
Let
d -----> the length of the diagonal of the inside square
