(3a²+6ab-24²)= 3a(a+2b)x(4b)
The ratio is 0.394 cm. / 1 in.
Answer:
The range for the equation is all real numbers.
Step-by-step explanation:
The range of an equation is the set of y-values that you can get by plugging in all possible x-values.
Another way to put it is, when you graph the equation, whatever y-values the line produces, is its range.
Graphing y=2x-3, you can see it is a graph with a positive slope that extends from negative infinity y-value to positive infinity x-value.
Answer:
The two numbers are 10 and 6.
Step-by-step explanation:
Let's begin by calling these two numbers x and y, and setting up a system of equations.
x-y=4
x*y=60
Now, you can rearrange the first equation to find the value of x expressed through y.
x=y+4
Now, you can substitute this into the second equation.
(y+4)*y=60
y^2+4y=60
y^2+4y-60=0
(y-6)(y+10)=0
y=6
x=6+4=10
Hope this helps!
Answer:
f(-121) = -5
f(31) = 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = ∛(x - 4)
f(-121) is x = -121
f(31) is x = 31
<u>Step 2: Evaluate</u>
f(-121)
- Substitute in <em>x</em>: f(-121) = ∛(-121 - 4)
- [Radical] Subtract: f(-121) = ∛(-125)
- [Radical] Evaluate: f(-121) = -5
f(31)
- Substitute in <em>x</em>: f(31) = ∛(31 - 4)
- [Radical] Subtract: f(31) = ∛27
- [Radical] Evaluate: f(31) = 3