Answer:
28
Step-by-step explanation:
We know that the heights and bases of all of the parallelograms will be the same because they are equal, therefore, since the height of 2 parallelograms is 14, the height of one parallelogram is 14 / 2 = 7. Since the areas of all of the parallelograms are congruent, the area of one parallelogram is 308 / 4 = 77. The parallelogram area formula is A = bh where A, b and h are area, base and height respectively and we know both the area and height so we need to solve for b. Doing so we get 77 = b * 7 so that means b = 11. The length of y is two bases + 6 and since we know the base is 11, y = 11 * 2 + 6 = 22 + 6 = 28.
Answer:
Its the first option.
Step-by-step explanation:
120 is not a perfect square.
Its close to one though - 121 is a perfect square ( 11 * 11 = 121).
(8 x 320)^1/3
(2560)^1/3
(64*40)^1/3
64^1/3 *40^1/3
4 * (8^1/3) * 5^1/3
4 * 2 * 5^1/3
8 *5^1/3
None of your choices are written correctly
If the two triangles are similar you can use a proportion to solve for the length of the legs.

=

Now, you would cross multiply to get
4x=18
Now, you simplify that using the division property of equality.
You end up with
x=4.5
Therefore, the legs of the triangle with a base of 9 inches will each be 4.5 units long.
let's firstly convert the mixed fractions to improper fractions, and then subtract.
![\bf \stackrel{mixed}{10\frac{1}{3}}\implies \cfrac{10\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{31}{3}}~\hfill \stackrel{mixed}{13\frac{1}{2}}\implies \cfrac{13\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{27}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{27}{2}-\cfrac{31}{3}\implies \stackrel{\textit{using the LCD of 6}}{\cfrac{(3)27~~-~~(2)31}{6}}\implies \cfrac{81~~-~~62}{6}\implies \cfrac{19}{6}\implies 3\frac{1}{6}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B10%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B10%5Ccdot%203%2B1%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B31%7D%7B3%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B13%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B13%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B27%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B27%7D%7B2%7D-%5Ccfrac%7B31%7D%7B3%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%206%7D%7D%7B%5Ccfrac%7B%283%2927~~-~~%282%2931%7D%7B6%7D%7D%5Cimplies%20%5Ccfrac%7B81~~-~~62%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B19%7D%7B6%7D%5Cimplies%203%5Cfrac%7B1%7D%7B6%7D)