Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Answer:
brackets, then Parenthesis then the FIRST Multiplication then the division and then math and sub and so on a so for
Step-by-step explanation:
Answer:
n = -2
Step-by-step explanation:
4n + 12 = 4
Subtract 12 from both sides.
4n = -8
Divide both sides by 4.
n = -2
Answer:
Primul copil are 6 lei, al doilea are 12 lei, al treilea are 27 de lei.
Step-by-step explanation:
Lăsați suma primului copil să fie x.
Lăsați suma al doilea copil să fie y.
Lăsați suma al treilea copil să fie z.
Trei dintre ei au 45 de lei în total.
Aceasta înseamnă că:
x + y + z = 45 ________(1)
Al doilea are de două ori valoarea primului:
y = 2x
Al treilea are cu 15 lei mai mult decât al doilea:
z = 15 + y
=> z = 15 + 2x
Puneți valoarea y și z în (1):
x + 2x + 15 + 2x = 45
5x = 45 - 15 = 30
x = 30 / 5 = 6 lei
=> y = 2 * 6 = 12 lei
=> z = 15 + 12 = 27 lei
Primul copil are 6 lei, al doilea are 12 lei, al treilea are 27 de lei.
