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Sauron [17]
3 years ago
14

The sum of the measures of two acute angles is always greater than 90 degrees

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

One acute angle will always measure between 0° and 90° . Two acute angles can sum to be either greater than, less than, or equal to a right angle. Two acute angles can be complementary angles (adding to 90° ). Two acute angles alone cannot sum to make a straight angle (180° )

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the graph shows the speed of a vehicle during the final 50 seconds of a journey at the start of the 50 seconds the speed is k me
Simora [160]

Answer:

a) 27 m/s

b) 30 m/s

c)   i) 3

     ii) Deceleration

Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey.  At the start of the 50 seconds the speed is k metres per second.  The distance travelled during the 50 seconds is 1.35 kilometres.

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(b) Work out the value of k.

(c) (i) Calculate the gradient of the graph in the final 10 seconds of the journey

    (ii) Describe what this gradient represents

Answer:

The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m  

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

Total \ distance=Total\ area=Area\ of \ rectangle+Area\ of \ triangle\\Total \ distance=(length *breadth)+\frac{1}{2}base*height\\1350 \ m=(40*k)+0.5*10*k\\1350=40k+5k\\45k=1350\\k=1350/45\\k=30\ m/sc) i) The gradient in the last 10 seconds is the ratio of change in speed to change in time

Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40}  \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

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Convert the following equation into<br> standard form.<br> y = -5x + 2<br> 5x + [?]y = [ ]
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Answer:

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Step-by-step explanation:

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