A pyramid has a rectangular base
2 answers:
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Answer:
Step-by-step explanation:
-p(d+z)=-2z+59
-pd-pz=-2z+59
lets bring all z integers on one side
-2z+pz = -pd-59
z(-2+p)=-pd-59
z = (pd-59) / (-2+p)
Answer:
Step-by-step explanation:
-p(d+z)=-2z+59
-pd-pz=-2z+59
lets bring all z integers on one side
-2z+pz = -pd-59
z(-2+p)=-pd-59
z = (pd-59) / (-2+p)