A parabola had a vertex at (3,4) and passes through the point (5,-4) what is the standard form equation for the parabola.. help
1 answer:
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Answer:
y = - x +
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 4y = 5x + 3 into this form by dividing the 3 terms by 4
y = x +
← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= -
, thus
y = - x + c ← is the partial equation
To find c substitute (3, - 2) into the partial equation
- 2 = - + c ⇒ c = - 2 +
=
y = - x +
← equation of perpendicular line
ANSWER
The maximum y-value is 0.
EXPLANATION
The domain of the given absolute value function is (-∞, ∞) .
This means the function is defined for all real values of x.
The range of the function is (-∞, 0].
This can be rewritten as
This means that, the highest y-value on the gray of this absolute value function is 0.
Hence the maximum y-value of the function is 0.