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Kruka [31]
3 years ago
10

The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales

representatives make an average of 37 sales calls per week on professors. Several reps say that this estimate is too low. To investigate, a random sample of 41 sales representatives reveals that the mean number of calls made last week was 40. The standard deviation of the sample is 5.6 calls. Using the 0.025 significance level, can we conclude that the mean number of calls per salesperson per week is more than 37? H0: μ ≤ 37 H1: μ > 37 Compute the value of the test statistic. (Roun
Mathematics
1 answer:
mihalych1998 [28]3 years ago
4 0

Answer:

We conclude that the mean number of calls per salesperson per week is more than 37.

Step-by-step explanation:

We are given that the Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales representatives make an average of 37 sales calls per week on professors.

To investigate, a random sample of 41 sales representatives reveals that the mean number of calls made last week was 40. The standard deviation of the sample is 5.6 calls.

<em><u>Let </u></em>\mu<em><u> = true mean number of calls per salesperson per week.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq 37   {means that the mean number of calls per salesperson per week is less than or equal to 37}

<u>Alternate Hypothesis,</u> H_A : \mu > 37   {means that the mean number of calls per salesperson per week is more than 37}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of calls made last week = 40

             s = sample standard deviation = 5.6 calls

             n = sample of sale representatives = 41

So, <em><u>test statistics</u></em>  =   \frac{40-37}{\frac{5.6}{\sqrt{41} } }  ~ t_4_0

                               =  3.43

Hence, the value of test statistics is 3.43.

<em>Now at 0.025 significance level, the t table gives critical value of 2.021 at 40 degree of freedom for right-tailed test. Since our test statistics is more than the critical value of t as 3.43 > 2.021, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the mean number of calls per salesperson per week is more than 37.

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5 0
2 years ago
Factor the expression below.
Gnom [1K]

Answer:

A. (x-5)(x-5)

Step-by-step explanation:

We need to factor x^2-10x+25 into the form (x+y)(x+y) where 2y=-10 and y^2=25

2y=-10

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So this becomes (x-5)(x-5)

Hope this helped!

4 0
3 years ago
Read 2 more answers
Please help me! Giving brainliest!
oksano4ka [1.4K]

Using it's formula, the surface area of the figure is:

A. S=2332 m²

<h3>What is the surface area of a rectangular prism?</h3>

The surface area of a rectangular prism of dimensions l, w and h is given by:

S = 2(lw + lh + wh)

In this problem, the dimensions are:

35m, 9m, 16m

Hence the surface area of the rectangular prism is:

S = 2(35 x 9 + 35 x 16 + 16 x 9) = 2038 m².

<h3>What is the surface area of a cube?</h3>

The surface area of a cube of side length l is given by:

S = 6l².

In this problem, we have that l = 7 m, hence the surface area is:

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T = 2038 m² + 294 m² = 2332 m².

Which means that option A is correct.

More can be learned about surface area at brainly.com/question/13030328

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Hunter-Best [27]
Subtract the y-coordinates. This is the rise.
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Subtract the y-coordinates: -6 - 15 = -21. rise = -21
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slope = rise/run = -21/3 = -7
6 0
3 years ago
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