factor 20 out of 20cx*3 =540y*3
so you get 20(cx*3=540y*3) if that is what you are looking for
Total income is $70/week. $20 of that goes towards the cost of gas. Thus, the net earnings were $50 for the week.
$50
------------------- = $5 per hour
10 hours
= 12x + 15y because 3 x 4x = 12x and 3 x 5y = 15y
Answer:
A sample size of 385 is needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.96.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
You feel that a reasonable estimate of the standard deviation is 10.0 hours.
This means that 
What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?
A sample size of n is needed. n is found when M = 1. So





Rounding up:
A sample size of 385 is needed.
You can say : 15/100 = 12/? ⇒ ?=12*100/15 ⇒ ? = 80 so 15% of 80 is 12 :)))
i hope this is helpful
have a nice day