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2 years ago

15

Help me with this question.

1 answer:

Elanso [62]2 years ago

4 0

Answer : T = 2,116 miles

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If the sum of the interior angle of a polygon is 1800 how many sides does it have

Verdich [7]

Answer: 12 sides

Step-by-step explanation:

The sum of the interior angles of a polygon is 180(n-2), where n is the number of sides

$180(n-2)=1800\\\\n-2=10\\\\n=12$

6 0

1 year ago

Please answer it for me or show me how to do it? I will mark you branliast answer !!

klasskru [66]

Answer:

25

Step-by-step explanation:

If HI and IJ are both the same and meet at the same point, the triangles would be the same.

7 0

3 years ago

The system of equations can be solved using linear combination to eliminate one of the variables. 2x − y = −4→10x − 5y = −20 3x

tester [92]

Answer:

Option D is correct.

13x = 39

Step-by-step explanation:

The system of equation is given:

$2x-y = -4$ ....[1]

$3x+5y = 59$ .....[2]

Multiply equation [1] by 5 to both sides we have;

$10x-5y = -20$ .....[3]

Using elimination method:

Add [2] and [3] equations to eliminate y and solve for x, we have;

$13x = 39$

Divide both sides by 13 we get;

x = 3

Substitute x in [1] we have;

2(3)-y = -4

6-y = -4

Subtract 6 from both sides we have;

-y = -10

Divide both sides by -1 we have;

y = 10

⇒Solution: (3, 10)

Therefore, an equation can replace 3x+5y = 59 in the original system and still produce the same solution is,

13x = 39

6 0

3 years ago

Read 2 more answers

Use the add-on method for determining interest on a loan of $1730, with an annual rate of 12% and a term of 2 years. Then,

slamgirl [31]

In 2 years, you will have $2,170.11

3 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago