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g100num [7]
3 years ago
15

Help me with this question.

Mathematics
1 answer:
Elanso [62]3 years ago
4 0
Answer : T = 2,116 miles
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360 km^2

Step-by-step explanation:

(this is a rectangular prism)

Volume = length * width * height

Volume = 5 * 6 * 12

Volume = 360 km^2

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Timothy spent $68 at Macy's. His purchases include a pair of jeans at $32 and 2 t-shirts at $x each. how much for each t-shirt.
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idk

Step-by-step explanation:

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3 years ago
Which statements about the graph of the function f(x) = –x2 – 4x + 2 are true? Check all that apply.
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Statements 2, 3, and 5 are true based on the graph of this function.

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In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0
3 years ago
How do you do: -6(6a-5)=-2(8-5a)
devlian [24]

Answer:

a = 1

Step-by-step explanation:

1. distribute the -6 on the left into the parentheses. you should get -36a + 30.

2. on the side right of the =, distribute the -2 to get -16 + 10a.

now it should look like -36a + 30 = -16 + 10a.

3. move the terms over to isolate the a value. subtract 30 to the right side to get -46 (-36a=-46+10a)

4. move the 10a on the right to the left by subtracting it to the other side.

(-46a=-46)

5.divide by -46 to get a=1

7 0
3 years ago
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