Simplify the expression below. (2y+1)^2-4y^2+2 A. 4y+3 B. 2y+3 D. -1
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This is a quadratic formula with a general form of a²x + bx + c = 0. For quadratic equations, we can solve for its two roots using the quadratic formula shown in the attached picture.
a = -3
b = -4
c = -4
x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) = <em>2 + √-32/2</em>
x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =<em> 2 - √-32/2</em>
a = -3
b = -4
c = -4
x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) = <em>2 + √-32/2</em>
x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =<em> 2 - √-32/2</em>