Answer:
One is a = 2, b = 3 AND another one is a = 11, b = 12
Step-by-step explanation:
They all fit this description. b = 1+a
Answer:
Option C, 6.5
Step-by-step explanation:
<u>Step 1: Substitute y in the equation 3x - 5y = 22</u>
3x - 5y = 22
3x - 5(-5x + 32) = 22
3x + 25x - 160 + 160 = 22 + 160
28x / 28 = 182 / 28
x = 6.5
Answer: Option C, 6.5
Answer:
-1
Step-by-step explanation:
|x-4|=x-4 when x-4 is positive or zero.
|x-4|=-(x-4) when x-4 is negative or zero.
x-4 is positive or zero means:
x-4>=0
Add 4 on both sides gives:
x>=4
x-4 is negative or zero means:
x-4<=0
Add 4 on both sides gives:
x<=4
Now we are approaching values of 4 from the left which means these values are less than 4 which makes x-4 negative.
So we are using:
|x-4|=-(x-4) when x-4 is negative or zero.
As x approaches 4 from left we have:
|x-4|/(x-4)=-(x-4)/(x-4)=-1.
Yint is where the line crosses the y axis or where x=0
set x=0
3y+4x=15
x=0
3y+4(0)=15
3y+0=15
3y=15
divide by 3
y=5
yint is (0,5) or at y=5
Answer:
no
Step-by-step explanation:
