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2 years ago

If sina-Cosa= o find coseca.

Mathematics

1 answer:

oee [108]2 years ago

6 0

Answer:

cscα=√2

Step-by-step explanation:

Problem: If sinα-cosα=θ find cscα

Solution:

sinα-cosα=θ

sinα=cosα

sinα=sin(90-α)

If α<90, then:

α=90-α

2α=90

α=45°

sin(45°)

1/sin(45°)

csc(45°)

√2

Therefore, cscα=√2 if sinα-cosα=θ

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Step-by-step explanation:

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1 year ago

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3 years ago

Priya bought x grams of flour. Clare bought 3/8 more than that. Select one equation that represent the relationship between the

statuscvo [17]

Answer:

The relationship ship equation:

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Step-by-step explanation:

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3 0

2 years ago

Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)

Klio2033 [76]

Answer:

$(g\circ h)(x)=-x^2-x-3$

Step-by-step explanation:

So we have the two functions:

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And we want to find:

$(g\circ h)(x)$

This is the same thing as:

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So, substitute h(x) into g(x):

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Distribute the negative:

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6 0

2 years ago

Read 2 more answers

(60 points)

natka813 [3]

Answer:

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

$6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}$

8 0

3 years ago

If sina-Cosa= o find coseca.​

If sina-Cosa= o find coseca.