hello ....
the equation of a plane that is ; ax+by+cz +d =0
the vector perpendicular to this plane is : V(a,b,c)
in this exercice ; a = -4 b= -4 c = -1
then: the equation of a plane that is ; -4x-4y-z +d =0
but the plane passing through the point (−2,−5,5) :
-4(-2)-4(-5)-(5) +d =0
23+d =0
d =-23
the equation of a plane is : -4x-4y-z-23 =0
Answer:
x=11/2
Step-by-step explanation:
Answer:
The measures of each would be:
105° and 75°
Step-by-step explanation:
Supplementary angles are two angles whose measures sum up to 180° or they form a straight line.
So if an angle measures 30° less than the measure of its supplementary, it wold mean that both angles together is equal to 180°.
∠1 = x
∠2 = x-30°
∠1 + ∠2 = 180°
So here we plug in our equations:
∠1 + ∠2 = 180°
x + x - 30° = 180°
2x - 30° = 180°
We solve for the x then:
Add 30° on both sides of the equation:
2x - 30° + 30° = 180° + 30°
2x = 210°
Divide both sides by 2:
2x/2 = 210°/2
x = 105°
∠1 = 105°
Now we solve for the second angle:
∠1 + ∠2 = 180°
105° + ∠2 = 180°
Subtract 105° from both sides of the equation:
105° + ∠2 - 105° = 180° - 105°
∠2 = 75°
Answer:
144
Step-by-step explanation:
PEMDAS
(12)^2
144
