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stepan [7]
3 years ago
6

Can some one help me with THIS??????

Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

65

Step-by-step explanation:

The first one is 25

The other one is 90

So

25+90+C=180

C=180-90-25=65

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Indicate the answer choice that best completes the statement or answers the question.
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What is the value of the function at x = -2?
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Read 2 more answers
a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks​
Inessa [10]
<h3>The distance between two landmarks is 123 meters</h3>

<em><u>Solution:</u></em>

We have to find the distance between two landmarks

<em><u>Use the law of cosines</u></em>

The third side of a triangle can be found when we know two sides and the angle between them

c^2 = a^2 + b^2 - 2ab\ cos c

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123

Thus, the distance between two landmarks is 123 meters

8 0
4 years ago
In a cafeteria, 3/10 of the students ate eating salads, and 3/5 are eating sandwiches. There are 30 students in the cafeteria. H
Daniel [21]

Answer:

1/10 or 3kids

Step-by-step explanation:

First you want to take 3/5 into 10nths so you do 3/5 times two and you get 6/10 then you add up 6/10 and 3/10 and you get 9/10. 30÷ 9/10 is 27 so 3 kids are having other things

5 0
3 years ago
What’s the area and the perimeter and of the triangle?
asambeis [7]

Answer:

Area = 3.3998

Perimeter = 2.9

Step-by-step explanation:

A method for calculating the area of a triangle when you know the lengths of all three sides.

Let a,b,c be the lengths of the sides of a triangle. The area is given by:

Area =  √  p  ( p − a )  ( p − b )  ( p − c )    

where p is half the perimeter, or  

a + b + c / 2

 p = 1.7 + 1.7 + 2.4 / 2 = 5.8 /  2 = 2.9

a = Area = 3.3998

Heron was one of the great mathematicians of antiquity and came up with this formula sometime in the first century BC, although it may have been known earlier. He also extended it to the area of quadrilaterals and higher-order polygons.

8 0
2 years ago
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