Okay so first you want to simplify the given equation (7x+3y)(7x-3y)
in order to do this you multiply the first number of the first equation (7x) with the first number of the second equation (7x) this gives you 49x^2
Now you want to multiply the second number of the first equation (3y) by the second number of the second equation (-3y) this gives you -9y^2
Its as easy as pie!
Answer: with the power of 9 − 1 with the power of 6
Sorry if im wrong and have a wonderful day!!!!!
do you mind telling me the question?
We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!
We are given with ;
Take LCM on both sides :
<em>Multiplying</em> both sides by <em>10</em> ;

Can be <em>further written</em> as ;
Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

