X^3-7y-7x+y, is the farthest you can simplify it to.
A)
acd = a + b
(Get the value of B from image)
136 = a + 56
(Subtract 56 from both sides)
136 - 56 = a
(Solve 136 - 56)
a = 80
(C is supplementary with 136)
136 + c = 180
(Subtract 136 from both sides)
c = 180 - 136
(Solve 180 - 136)
c = 44
Therefore:
a = 80 and c = 44
B)
egh = e + f
(Get values from image)
63 = e + 23
(Subtract 23 from both sides)
63 - 23 = e
(Solve 63 - 23)
e = 40
(G is supplementary with 63, supplementary angles equal 180
63 + g = 180
(Subtract 63 from both sides)
g = 180 - 63
(Solve 180 - 63)
g = 117
Therefore
e = 40 and g = 117
Answer:
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Step-by-step explanation:
For any value of x g(x) is always greater than h(x) and for any value of x, h(x) will always be greater than g(x) are not true.
The given function is:
g(x) = x^2 and h(x) = –x^2
x=0
g(0)=(0)^2 = 0
h(0)= -(0)^2 = 0
Now check the condition for x = -1
put x =-1 in the given functions.
g(x)=x^2
g(-1) = (-1)^2 = 1
h(x)= -x^2
h(-1) = -(-1)^2 = -1
g(x)>h(x)
Now take a positive value of x= 3
Put the value in the given functions:
g(3) = (3)^2 = 9
h(3) = -(3)^2 = -9
g(x)>h(x)
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x)....
Answer:
B. 6x2+x+7
Step-by-step explanation:
combine like terms
3x^2+3x^2= <u>6x^2</u>
<u>x</u>
3+4=<u>7</u>
R=sq(x2+y2)
teta=tan-1(y/x)
so r=sq(4+9)=sq(13)
teta=tan-1(3/2)
and so on