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True [87]
3 years ago
15

Solve for x: x + -4 = 11

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
Solve for x
x-4=11
x=11+4
x=15

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Mkey [24]
2 meters. Think of it like 6×1/3, or 6÷3.
4 0
3 years ago
Please help need to know the answer to this supposedly is 9 + (9x36) 333 but I don’t get it
Ahat [919]

Answer:

459

Step-by-step explanation:

First line:

clock showing 9 o'clock + clock showing 9 o'clock + clock showing 3 o'clock = 9 + 9 + 3 = 21

Second line:

The calculators look exactly the same.

3 * calculators = 30

1 calculator = 10

Third line:

1 bulb + 1 bulb - 1 bulb = 15

Since 1 bulb - 1 bulb = 0, we have 1 bulb + 0 = 15, or

1 bulb = 15

Last line:

Clock showing 9 o'clock = 9

Calculator = 10

3 bulbs = 3 * 15 = 45

Total = 9 + 10 * 45 = 9 + 450 = 459

7 0
3 years ago
Consuela and her three friends order 2 pizzas. Consuela cuts each pizza into 8 equal slices. She saves 2 slices of pizza for her
Akimi4 [234]
Let
x-------------->  the number of slices eating by Consuela  and her <span>three friends

we know that
[total slices]=8*2=16 slices
</span><span>[slices of pizza for her older brother]=2
x=16-2=14 slides
</span><span>Consuela and her friends share the rest of the pizza, each eating the same number of slices---------> 14/4= 3.5 slides of pizza each  (</span><span>this part is not necessary, but it is shown in a didactic way)
</span><span>
the question is 
</span><span>What fraction of the 2 pizzas is left over?
</span>[slices of pizza for her older brother]/[total slices]=2/16=1/8
<span>
the answer is (1/8)

</span>
8 0
3 years ago
Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
3 years ago
Find the mean of the weights.<br> 0.8158 0.8194 0.8164 0.8175 0.7911 0.8144 0.8123
denis23 [38]

Answer:

0.81241

if i'm wrong i'm rlly rlly sorry!!

4 0
3 years ago
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