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SpyIntel [72]
2 years ago
11

Determine the length of side QR in the following triangle

Mathematics
1 answer:
Jobisdone [24]2 years ago
3 0

The length of the side QR in the task content can be determined as; 12.22cm.

<h3>What is the length of the third side QR?</h3>

It follows from the task content that 2 lengths and one included angle are given in the task content. It therefore follows that the length of side QR can be evaluated by the cosine rule as follows;

QR² = 13² + 4² - (2×4×13×cos70)

QR = √149.4

QR = 12.22cm

Read more on cosine rule;

brainly.com/question/23720007

#SPJ1

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Graph the line that passes through the points (-4, -1) and (-4, 2) and determine the equation of the line.​
My name is Ann [436]

Answer:

X = -4

Step-by-step explanation:

7 0
2 years ago
What is the area of a rectangle with width 25 inches and length 35 inches? 1/5 in² 6/25 in² 6/10 in² 2 in²
zhenek [66]
By looking at ur answer choices, I am assuming the width is 2/5 inches and the length is 3/5 inches.

A = L * W
A = 3/5 * 2/5
A = 6/25 in^2 <==
8 0
3 years ago
Read 2 more answers
Which describes the solution of a system of equations for two lines with the same slope and the same y-intercepts?
olganol [36]
The answer is B. Infinitely many solutions.  <span />
8 0
3 years ago
Pre cacl pleaseeeee help. the options are in the attachments as well
ivanzaharov [21]

Answer:

The values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of x so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is \pi. Then, the  vertical asymptotes associated with function cosecant are located in the values of x of the form:

x = 0\pm \pi\cdot i, \forall \,i\in \mathbb{N}_{O}

In other words, the values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

3 0
3 years ago
Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth
katrin2010 [14]
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] / <span> <span> <span> 1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) = <span> <span> <span> 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span> <span> <span> <span> 154.85

</span></span></span>Finally, calculating the third angle is quite easy
Angle C =  180 - Angle (A) - Angle(B)
Angle C =  180 - 15.475 - 154.85
Angle C =  9.675

Source:
http://www.1728.org/trigtut2.htm


6 0
2 years ago
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