Each of the 90 fourth-grade students at North Elementary read 30 books over the school year.

what is the measure of angle 3 if the measure of angle 6 is (2x-5) and the measure of angle 8 is (x+5)?

strojnjashka [21]

Answer: 115

Step-by-step explanation: just did it on edg

4 0

3 years ago

Plz help

yKpoI14uk [10]

Answer:

1. A point you can't move at all, a line you can only move back and forth in the same direction. Yes it is accurate for its characteristics because points and lines have no set definition for them

2. When you are on a point you can not travel at all in any direction while staying on that point. That means you have zero options to travel in. That is why it is said you have zero dimensions.

3. Normal space refers 3 dimensional space that extends beyond the three dimensions of length, width, and height.

4. If you can move backward, forwards, up and down in two different directions it is considered two dimensional. The two dimensional figure is considered a plane. For example, if you took a piece of paper that extended forever in every direction, that in a geometric a sense, is a plane. The piece of paper itself is itself, finite, and you could call the piece of paper a plane segment because it is a segment of an entire plane.

8 0

3 years ago

Write an inequality equation: Lyla has $100 in her bank account. She wants to buy presents that are $5 each. Wrapping paper will

lisov135 [29]

(100 - 25) / 5
15 presents

6 0

2 years ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

(c) Here, also 8 computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

Can anyone help me with this? please.

victus00 [196]

Acute right complementary adjacent

7 0

3 years ago

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