A function will have at most, one y-intercept. O True O False Please answer ASAP thanks

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

5 0

Answer: True. . . . . .

zmey [24]3 years ago

5 0

Answer:

It's FALSE, I guess. Cause function x=a (a=const) does not have y-intercept

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Pleaseee helppp with thisss asappp

Hoochie [10]

We are given with a equation of Circle and we need to find it's radius and it's equation in standard form . But , let's recall , the standard equation of a circle is ${\bf (x-h)^{2}+(y-k)^{2}=r^{2}}$ where (h,k) is the centre of the circle and radius is r . Proceeding further ;

${:\implies \quad \sf x^{2}+12y+22x+y^{2}-167=0}$

Collecting x terms , y terms and transposing the constant to RHS ;

${:\implies \quad \sf (x^{2}+22x)+(y^{2}+12y)=167}$

Now , as in standard equation their is a whole square , so we need to develop a whole square in LHS , for which we will use completing the square method , as coefficient of x² and y² is 1 , so adding 121 and 36 to LHS and RHS .

${:\implies \quad \sf (x^{2}+22x+121)+(y^{2}+12y+36)=167+121+36}$