Answer:
Step-by-step explanation:
Instead, since the divisor is in the form of 
, use what is called Synthetic Division. Remember, in this formula, 
gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 −5 7 −12
↓ 4 −4 12
_______________
1 −1 3 0 →
You start by placing the 
in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an 
, the −1 [
] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of .
I am joyous to assist you anytime.
Answer:
6040
Step-by-step explanation:
You can find out in two different ways, either use scientific notation or a calculator. If you go 3 steps to the right (since it's a positive power) you will get 6040. Hope this helped. :)
Answer: 
Step-by-step explanation:
You need to use the following formula that is used to find the area of a trapezoid:
Where "M"and "m" are the bases of the trapezoid and "h" is the height of the trapezoid.
Based on the information given in the exercise, you can identify that:
Knowing these values, you can substitute them into the formula:
Finally, you must evaluate in order to find its area. This is:
Answer:
It's not, the Median is 5 the mean is 10!
Step-by-step explanation:
The median is also the number that is halfway into the set. To find the median, the data should be arranged in order from least to greatest. If there is an even number of items in the data set, then the median is found by taking the mean (average) of the two middlemost numbers.
Answer:
16 feet is the correct answer to this problem.
