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fgiga [73]
2 years ago
13

Two is subtracted from a number, and then the difference is multiplied by 5. The result is 30

Mathematics
2 answers:
Vanyuwa [196]2 years ago
6 0

Answer:

8

Step-by-step explanation:

8-2=6

6x5=30

Svetradugi [14.3K]2 years ago
6 0

Answer:

y = 8

Step-by-step explanation:

(y - 2) × 5 = 30

(y - 2) × 5 ÷ 5 = 30 ÷ 5

y - 2 = 6

y - 2 + 2 = 6 + 2

y = 8

<u>Check</u>

(8 - 2) × 5 = 30

6 × 5 = 30

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A rectangle patio is surrounded on three sides by a fence. If the areas of the patio is 45 m sq and the total of fence is 19m wh
Eddi Din [679]
LW = 45
L + 2W = 19
L = 19-2W

substituting for L :-
W(19-2W) = 45

-2W^2 + 19W = 45

2W^2 - 19W + 45 = 0 
W = 5 or 4.5

If W = 5, L = 9
If W = 4.5, L = 10

So there are 2 possible answers.


3 0
3 years ago
(6g)^3<br> Simplify the expression.
icang [17]
216g^3

Hope this helps
8 0
3 years ago
Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
lukranit [14]

The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

8 0
2 years ago
Prove algebraically that the recurring decimal 0.72 =8/11
miskamm [114]

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring decimal placed after the decimal point.

let x = 0.7272.... (1) ← multiply both sides by 100

100x = 72.7272... (2)

Subtract (1) from (2) thus eliminating the recurring decimal

99x = 72 ( divide both sides by 99 )

x = \frac{72}{99} = \frac{8}{11}

7 0
3 years ago
Read 2 more answers
Mia and John are selling boxes of apples. They have small boxes and large boxes. Mia sells 6 small boxes and 2 large boxes for a
kvasek [131]

so

6s+2l = 28

4s+5l=  37

eliminate 6s+2l=28 by dividing all numbers by 6

u get s= -1/3 l + 14/3

49-1/3l=14/3) + 5l =37

L=5

s= -1/3(5) + 14/3

s=3

l=5

     

6 0
3 years ago
Read 2 more answers
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