The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.
Answer:
She didn't take the LCM, made an error while cross multiplying
x = -6
Step-by-step explanation:
a)she didn't take the LCM before cross multiplying.
Also, didn't cross multiply correctly
b) 1 -2/(x-2) = (x+1)/(x+2)
1 - 2/(x-2) = (x+2-1)/(x+2)
1 - 2/(x-2) = 1 - 1/(x+2)
1 - 2/(x-2) = 1 - 1/(x+2)
-2(x+2) = -1(x-2)
-2x-4 = -x+2
x = -6
