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timama [110]
3 years ago
5

Help me please i dont understand

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0
So since they mentioned tangent I am guessing you need to use sin and cosine.

Usually we use sin, cosine and tan when we have an angle and we need to find one of the sides (look at the picture below)

But since now we have the sides and we need to find the angle, we need to use something called sin inverse or arcsin.

X=sin^-1 (6/14)

Note: sin^-1 is the same as saying sine inverse same as saying arcsin.

If we use this it will give us the required angle..

X=25.377 or X=25.4 degrees

Please do yourself a favour and compare it to the one below...finding the sides (because in the case we have the angle and not the sides we don’t use sine inverse)

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The difference of a number x and 9 is fewer then 4
Sav [38]
The equation would be:
x - 9 < 4
Simplify (add 9)
Solution: x < 13
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3 years ago
You want to buy three books that are on sale at 20% off. The original prices of the books are $2.50, $4.95, and $6.00. How much
Anon25 [30]

First add the prices of the original books.

2.5+4.95+6=11.45

Find 20% of 11.45

=2.29

Therefore I saved $2.29

8 0
3 years ago
Please answer in only a fraction please..
fenix001 [56]

Answer:

19/40

Step-by-step explanation:

1.9*(1/4) =0.475

0.475=19/40

3 0
2 years ago
Read 2 more answers
15 = -4p + 7<br><br><br> solving equation
Ratling [72]

Answer:

p = -2

Step-by-step explanation:

15 = -4p + 7

4p + 15 = 7

4p + 15 - 15 = 7 - 15

4p = -8

4p/4 = -8/4

p = -2

8 0
3 years ago
Read 2 more answers
The number of ways in which 4 squares can be chosen at random on a chess board such that they lie on a diagonal line?.
wariber [46]

The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:

The required number of ways:

= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))

= 2[2[ 1 + 5 + 15+35] + 70]

= 364

Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ4

5 0
1 year ago
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