The solution would be like this for this specific problem:
<span>period = 2π / b </span>
<span>Let’s presume that
frequency factor means angular frequency "b" </span>
and then;
<span>2π = 2π/b => b=1 </span>
<span>So, a sine function whose period is 2pi radians
<span>have a frequency factor of b = 1.</span></span>
Answer:
8a
Step-by-step explanation:
Given
5a + 3a ← factor out from each term
= (5a + 3a)
= 8a
First I would distribute the left part like so:
12x - 18 - (5x + 7)
Then I would distribute the right side like so: (I'm just distributing a negative sign)
12x - 18 - 5x - 7
Then I combine like terms like so: (12x and -5x)
7x - 18 - 7
Then I would combine the other like terms like so: (-18 and -7)
7x - 25
I hope that helps! Feel free to let me know if you have any questions! :3
- mathwizzard3
3 * 100 = 300 because it is only asking you to claculate 3*100
