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3 years ago

Lots of points math a few questions

Mathematics

2 answers:

Elenna [48]3 years ago

8 0

Answer:

first one is d second one is d third one is d fourth one is b fifth one is c sixth one is negative eleven and positive five

Step-by-step explanation:

MrRa [10]3 years ago

3 0

First one is d second one is d third one is d fourth one is b fifth one is c sixth one is negative eleven and positive five

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Jerome, kevin and seth shared a submarine sandwhich. Jerome ate 1/2 of the sandwich , kevin ate 1/3 of the sandwich, and seth at

Paul [167]

Given:

Jerome ate 1/2 of the sandwich , Kevin ate 1/3 of the sandwich, and Seth ate the rest.

To find:

The ratio of jerome's share to kevin's share to seth's share.

Solution:

Jerome ate 1/2 of the sandwich. So,

Jerome's share = $\dfrac{1}{2}$

Kevin ate 1/3 of the sandwich. So,

Kevin's share = $\dfrac{1}{3}$

Seth ate the rest. So,

Seth's share = $1-\dfrac{1}{2}-\dfrac{1}{3}$

= $\dfrac{6-3-2}{6}$

= $\dfrac{1}{6}$

The ratio of jerome's share to kevin's share to seth's share is:

$\dfrac{1}{2}:\dfrac{1}{3}:\dfrac{1}{6}$

To simplify the ratio multiply the ratio by 6.

$\dfrac{1}{2}\times 6:\dfrac{1}{3}\times 6:\dfrac{1}{6}\times 6$

$3:2:1$

Therefore, the ratio of jerome's share to kevin's share to seth's share is 3:2:1.

8 0

3 years ago

Find the slope of the line through the pair of points. (9,3) and (19,-17)

Ilya [14]

Answer:

m=-2

the slope is -2

Step-by-step explanation:

8 0

3 years ago

Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug

babymother [125]

Answer:

The total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case we need to determine the number of ways in which the drugs are assigned to each mouse.

It is provided that new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes.

Drug A is to be given to 22 mice.

Compute the number of ways to assign drug A to 22 mice as follows:

${60\choose 22}=\frac{60!}{22!(60-22)!}\\\\=\frac{60!}{22!\times 38!}\\\\=14154280149473100$

Now the remaining number if mice are: 60 - 22 = 38.

Compute the number of ways to assign drug B to 22 mice as follows:

${38\choose 22}=\frac{38!}{38!(38-22)!}\\\\=\frac{38!}{22!\times 16!}\\\\=22239974430$

Now the remaining number if mice are: 38 - 22 = 16.

Compute the number of ways to assign no drug to 16 mice as follows:

${16\choose 16}=\frac{16!}{16!(16-16)!}\\\\=1$

The total number of ways of assignment is:

$N = {60\choose 22}\times {38\choose 22}\times {16\choose 16}\\\\=14154280149473100\times 22239974430\times 1\\\\=314,790,828,599,338,321,972,833,000$

Thus, the total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

8 0

3 years ago

Please help asap im confused

solong [7]

Answer:

very beautiful question....

Option B

Step-by-step explanation:

X= 57-23=34

Answer

hope it helps

5 0

3 years ago

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The table represents the function

aksik [14]

Answer:

the function of 3 on the table is 1

3 0

3 years ago

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