Let dimes = d and quarters =q
D + q = 50
D= 50-q
0.10d + 0.25Q = 7.70
Replace d with 50-q:
0.10(50-q) + 0.25q = 7.70
Simplify:
5 -0.10q + 0.25q = 7.70
5 + 0.15q = 7.70
Subtract 5 from both sides:
0.15q = 2.70
Divide both sides by 0.15:
Q = 2.70 / 0.15
Q = 18
D = 50-18 = 32
There are 32 dimes and 18 quarters
Answer:
1311.88
Step-by-step explanation:
Feet:stories
883:70
x:104
To solve this we need to multiply 883 by 1.48 because this is what we multiplied 70 to get to 104
x=1311.88=1312
Answer:
Step-by-step explanation:
12 men and 18 women: x1; 14 days; y1
8 men and 16 women: x2; ?; y2
12/18 simplified is equal to 2/3
8/16 simplified is equal to 1/2
This is a direct proportion, thus we can say that:
(1/2*14)/(2/3)=y2
7/(2/3)=10.5 days
I hope this helped you get out of homework trouble :D
OwO
So if you think about it, this problem isn't that hard. So say it's 12:59, the total sum of those digits would be 71. If it was 1:11, then the sum would be 3. If it was 3:47, the sum would be 50. So now, you have to find the time where it would be the least possible sum. that time would be 1:00 because 1+0+0=1
The probability of Event A is 5/10 which simplifies to 1/2.
The probability of Event B is 3/9 which simplifies to 1/3.
Because it says "and" we need to multiply them which gives us 1/2*1/3=1/6
