Based on the percentage that passed English and those who passed Mathematics and those who failed and passed both, the total number of students who appeared in the examination are 60 students.
The number of students who passed only in Math are 12 students.
<h3>What number of students sat in the exam?</h3>
This can be found as:
= Total who passed English only + Total who passed Math only + Total who failed both + Total who passed both
Assuming the total is n, the equation becomes:
n = 0.75n - 21 + 0.55n - 21 + 21 + 0.05n
n = 1.35n - 21
21 = 0.35n
n = 21 / 0.35
= 60 students
The number who passed mathematics only is:
= (60 x 55%) - students who passed both
= 33 - 21
= 12 students
Find out more on Venn diagrams at brainly.com/question/24581814
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Slope of line
m= (y2-y1)/(x2-x1)
=(-4--6)/(6--2)
=2/8
=1/4
Line in two point form
(y-y1)=m(x-x1)
y--2=(1/4)(x-6)
y+2=(1/4)(x-6)
simplify
4(y+2)=x-6 =>
x-4y-14=0
Alternatively, use the slope intercept form:
y--2=(1/4)(x-6) =>
y=(1/4)x - 3/2-2 =>
y=(1/4)x -7/2
I believe the answer would be B. 11 because you can see a pattern. Its just skipping.
Answer:
20:21
Step-by-step explanation:
Let's first start by converting each ratio so that the number of girls is the same
2:3
4:7
The least common multiple of 3 and 4 is 12 so...
8:12
12:21
We add 8 and 12 to get the number of junior members...
8+12=20
Then we put it in a ratio with the amount of adult members...
20:21
