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3 years ago

10

5x + 10 = 15 1. 3 2. 1 3. 5 4. 25

1 answer:

poizon [28]3 years ago

4 0

Answer:

$5x = 15 - 10 \\ 5x = 5 \div 5 \\ 5x = 1$

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Which are the solutions of the quadratic equation? x2 = 9x + 6

Lelechka [254]

X^2 = 9x + 6
x^2 - 9x - 6 = 0
use quadratic formula : (-b (+-) sqrt b^2 - 4ac) / (2a)
a = 1, b = -9, c = -6
now we sub

x = (-(-9) (+-) sqrt -9^2 - 4(1)(-6)) / 2(1)
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3 years ago

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A line contains points M(1, 3) and N(5, 0). What is the slope of MN? -4/3 -3/4 3/4 4/3

german

Answer:

Step-by-step explanation:

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3 years ago

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Miche found that most helicopters fly at speeds of less than 270 kilometers per hour. Her work is shown below. s > 270 A numb

almond37 [142]

Answer:

The inequality should be s<270.
The number line should be shaded to the left.

Step-by-step explanation:

Miche found that most helicopters fly at speeds of less than 270 kilometers per hour.

If s=speed of the helicopters

Then: s<270

Representing this on a number line:

We have an open circle at 270.

Everything to the left of the circle is shaded.

Since the options are not given, I would list the mistakes made by Miche.

The inequality should be s<270.
The number line should be shaded to the left.

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3 years ago

Paula walks 1/12 mile in 5/3 minutes. What rate is equivalent to the rate she walked?

mel-nik [20]

The rate that is equivalent to the rate Paula walked is 1/20 mile/minute OR 0.05 mile/minute

<h3>Calculating Rate </h3>

From the question, we are to determine the rate which is equivalent to the rate Paula walked

Using the formula,

$Rate = \frac{Distance}{Time}$

From the given information,

Distance = 1/12 mile

Time = 5/3 minutes

Putting the parameters into the formula, we get

$Rate =\frac{\frac{1}{12} }{\frac{5}{3} }$

$Rate = \frac{1}{12} \div \frac{5}{3}$

$Rate = \frac{1}{12} \times \frac{3}{5}$

$Rate = \frac{3}{60}$

$Rate = \frac{1}{20}$ mile/minute

Hence, the rate that is equivalent to the rate Paula walked is 1/20 mile/minute OR 0.05 mile/minute

Learn more on Calculating Rate here: brainly.com/question/21208007

#SPJ 1

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2 years ago

Find the oth term of the geometric sequence 5,--25, 125,

Genrish500 [490]

Given the geometric progression below

$5,-25,125,\ldots$

The nth term of a geometric progression is given below

$T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}$

From the geometric progression, we can deduce the following

$\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}$

To find the value of r, we will take ratios of two consecutive terms

$\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}$

To find the 9th term of the geometric, we will have that;

$\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}$

Hence, the 9th term of the geometric progression is 1953125

8 0

11 months ago