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yanalaym [24]
3 years ago
7

Calculate the median of the following data 18, 24, 55, 59, 34, 39, 22, 32, 57, If 55 is replaced by 33, calculate the new median

Mathematics
2 answers:
max2010maxim [7]3 years ago
4 0
The median with the number how they are and not being replaced is 37.7 with the 55 being replaced with 33 the new median is 35.3
Sliva [168]3 years ago
4 0

Answer:

34, and if 55 was replaced with 33, the new median would be 33.

Step-by-step explanation:

The median is the number that is in the middle of a data set, once the numbers are organized from least to greatest. If we put the numbers in order (18, 22, 24, 32, 34, 39, 55, 57, 59), the number in the middle is 34. If we do the same, but replace 55 with 33, (18, 22, 24, 32, 33, 34, 39, 57, 59), we get 33 as the median.

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Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
3 years ago
20. Q(-1, 4), R(-1, -9), S(11, -2), T(11, 6)
s2008m [1.1K]

Answer:

Parallel

Step-by-step explanation:

QR and ST both parallel to y axis.

3 0
3 years ago
Marta and Kim are sisters. Five years ago Kim's age was twice as great as martas age. If Marta is no m years old, what expressio
Hitman42 [59]

Answer:

y = 2m-5

Kim's age now is y = 2m-5

Step-by-step explanation:

Let m represent martas age now and y represent Kim's age now

Given;

Five years ago Kim's age was twice as great as martas age.

(y-5) = 2(m-5)

Solving for y;

y-5 = 2m-10

y = 2m-10+5

y = 2m-5

Kim's age now is y = 2m-5

5 0
3 years ago
8x=12+12Find the value of x​.​
djverab [1.8K]

Answer:

\sf\longmapsto \: x = 3

Step-by-step explanation:

\sf\longmapsto \: 8x = 24

\sf\longmapsto \: x =  \frac{24}{8}

\sf\longmapsto \: x = 3

5 0
2 years ago
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Question 1 answer: 5/3 miles per hour
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