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3 years ago

Phythagorean theorem HELPPPP PLSSSSS ASAPPP

Mathematics

2 answers:

attashe74 [19]3 years ago

4 0

Answer:

l = 9 cm

Step-by-step explanation:

Using Pythagoras' identity in one of the right triangles with legs width w, length l and hypotenuse h , then

l² + w² = h²

l² + 12² = 15²

l² + 144 = 225 ( subtract 144 from both sides )

l² = 81 ( take the square root of both sides )

l = $\sqrt{81}$ = 9

Bogdan [553]3 years ago

3 0

Answer:

Step-by-step explanation:

We know that we can use the Pythagorean theorem

a^2 + b^2 =c^2

where a and b are the legs and c is the hypotenuse

one of the legs is 12 and the hypotenuse (diagonal) is 15

a^2 + 12^2 = 15^2

a^2 +144 = 169

a^2 +144-144 =169-144

a^2 = 25

Taking the square root of each side

sqrt(a^2) = sqrt(25)

a = 5

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The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

A line contains the points R (-1, 8) S (1, 4) and T (6, y). Solve for y. Be sure to show and explain all work.

Nikitich [7]

Given:

A line contains the points R(-1, 8), S(1, 4) and T(6, y).

To find:

The value of y.

Solution:

Three points are collinear if:

$x_1(y_2-y_3)+x_2(y_3-y_2)+x_3(y_1-y_2)=0$

A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.

$-1(4-y)+1(y-8)+6(8-4)=0$

$-4+y+y-8+48-24=0$

$2y+12=0$

Subtract 12 from both sides.

$2y=-12$

Divide both sides by 2.

$y=\dfrac{-12}{2}$

$y=-6$

Therefore, the value of y is -6.

3 0

3 years ago

West high schools population is 250 students fewer then twice the population of East High school the two schools have a total of

gizmo_the_mogwai [7]

Answer:

1036 students

Step-by-step explanation:

Let the number of students at West High be "w" and the number of students at East High be "e"

West High population is 250 FEWER than TWICE of East High, we can write:

w = 2e - 250

Total students in both schools is 2858, so we can write 2nd equation as:

e + w = 2858

We can replace 1st equation in 2nd to get an equation in e, and find "e":

e + w = 2858

e + (2e - 250) = 2858

3e - 250 = 2858

3e = 2858 + 250

3e = 3108

e = 3108/3

e = 1036

Hence,

number of students attending East High School = 1036 students

3 0

3 years ago

The coordinates below represent two linear equations. How many solutions does this system of equations have? Line 1 x y –1 6 0 4

iren2701 [21]

I think you need to retype this one. The formatting makes this question difficult to understand.

8 0

4 years ago

7 of 10 - Under the amended Davis-Stirling Common Interest Development Act, in order to grant the exclusive use of a common area

Nata [24]

A. 67% is the correct answer

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3 years ago