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Karolina [17]
3 years ago
5

The mean height of women in a country​ (ages 20-​29) is 64.5 inches. A random sample of 75 women in this age group is selected.

What is the probability that the mean height for the sample is greater than 65 ​inches? Assume o=2.99.
Mathematics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

0.07378

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ/√n, where

x is the raw score = 65 inches

μ is the population mean= 64.5 inches

σ is the population standard deviation = 2.99

n = 75

z = 65 - 64.5 /2.99/√75

z = 0.5/0.345255461

z = 1.4482

Probability value from Z-Table:

P(x<25) = 0.92622

P(x>25) = 1 - P(x<25)

= 1 - 92622

= 0.07378

The probability that the mean height for the sample is greater than 65 ​inches is 0.07378

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "b2"   was replaced by   "b^2".  1 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (36 • (a2)) -  52b2

Step  2  :

Equation at the end of step  2  :

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Step  3  :

Trying to factor as a Difference of Squares :

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Proof :  (A+B) • (A-B) =

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Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  36  is the square of  6

Check : 25 is the square of 5

Check :  a2  is the square of  a1

Check :  b2  is the square of  b1

Factorization is :       (6a + 5b)  •  (6a - 5b)

Final result :

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