Purple and white make up less than 30 %
Answer:
216
Step-by-step explanation:
I believe that is the answer
Answer:
The probability is 0.0005.
Explanation:
The stated question is incomplete. The complete question is as follows.
<em>A manufacturer is developing a new type of paint. Test panels were exposed to various corrosive conditions to measure the protective ability of the paint. Based on the results of the test, the manufacturer has concluded that the mean life before corrosive failure for the new paint is 155 hours with a standard deviation of 27 hours. If the manufacturer's conclusions are correct, find the probability that the paint on a sample of 65 test panels will have a mean life before corrosive failure of less than 144 hours. </em>
The mean life is 155 hours. Hence, μ = 155.
The standard deviation is 27 hours. Hence, σ = 27.
The sample size in 65 test panels. Hence, n = 65.
We can use the central limit theorem to find the probability that the mean life before corrosive failure is less than 144 hours. By the central limit theorem:
P(X < 144) = P[(X - μ) / (σ / √n) < (144 - 155) / (27/√65)]
P(X < 144) = P(Z < -3.2846)
Using the Z-value table for normal distribution, this value turns out to be:
P(X < 144) = 0.0005
Answer: The answers are provided below
Step-by-step explanation:
15. 7c + 8d + 2c + 17d
= 7c + 2c + 8d + 17d
= 9c + 25d
16. 4(2m - 3p) + 12m + 7p
= 8m - 12p + 12m + 7p
= 8m + 12m -12p + 7p
= 20m - 5p
17. (15j +9z) - (12j + 6z)
= 15j - 12j + 9z + 6x
= 3j + 15z
18. 3y + 6.7x + y + 2.3x +10 - 7
= 6.7x + 2.3x + 3y + y + 10 - 7
= 9x + 4y + 3
19. 2b + (-6c) +5e - 11b + e+ 6c
= 2b - 11b - 6c + 6c + 5e + e
= -9b + 6e
Answer:
Step-by-step explanation:
11.04 I think