<em>You apply the </em><span><em>Pythagorean theorem and you'll have:</em>
<em>BC²=AB²+AC²</em>
<em>BC²=3²+7²</em>
<em>BC²=9+49</em>
<em>BC²=58</em>
<em>=> BC=√58</em>
<em>We cannot simplify √58 so the answer is<u> D) √58</u></em></span>
Answer:
C. 647 square units
Step-by-step explanation:
To find the shaded area, subtract the area of the unshaded square from the area of the octagon.
<u>Area of the octagon</u>
![\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}](https://tex.z-dn.net/?f=%5Ctextsf%7BArea%20of%20a%20regular%20polygon%7D%3D%5Cdfrac%7Bn%5C%3Al%5C%3Aa%7D%7B2%7D)
where:
- n = number of sides
- l = length of one side
- a = apothem
Given:
Substitute the given values into the formula and solve for A:
![\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}](https://tex.z-dn.net/?f=%5Cimplies%20%5Ctextsf%7BArea%7D%3D%5Csf%20%5Cdfrac%7B8%20%5Ccdot%2013%20%5Ccdot%2015.69%7D%7B2%7D)
![\implies \textsf{Area}=\sf \dfrac{1631.76}{2}](https://tex.z-dn.net/?f=%5Cimplies%20%5Ctextsf%7BArea%7D%3D%5Csf%20%5Cdfrac%7B1631.76%7D%7B2%7D)
![\implies \textsf{Area}=\sf 815.88\:\:square \:units](https://tex.z-dn.net/?f=%5Cimplies%20%5Ctextsf%7BArea%7D%3D%5Csf%20815.88%5C%3A%5C%3Asquare%20%5C%3Aunits)
<u>Area of the square</u>
![\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units](https://tex.z-dn.net/?f=%5Cimplies%20%5Ctextsf%7BArea%7D%3D%5Csf%2013%5E2%3D169%20%5C%3A%5C%3Asquare%20%5C%3Aunits)
<u>Area of the shaded region</u>
= area of the octagon - area of the square
= 815.88 - 169
= 646.88
= 647 square units (nearest square unit)
Answer:
The answer is 25.13 because the formula is C=2π4 (2 • pi • 4)
Step-by-step explanation:
Four is the radius so you multiply is by pi and two and get 25.13
43 since 7-2 =5
And 5 times 7 = 35 for the big box
And the top are 2 little boxes of an area of 4
35+8=43
Answer:
B
Step-by-step explanation: