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nevsk [136]
3 years ago
12

What is 2 3 of 99kg?

Mathematics
1 answer:
ozzi3 years ago
5 0

Step-by-step explanation:

\frac{2}{3}  \times  \frac{99}{1}  = 66 \: kg

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Is the following relation a function? {(0.3, 0.6), (0.4, 0.8), (0.3, 0.7), (0.5, 0.5)}
Readme [11.4K]

Answer:

no

Step-by-step explanation:

To be a function, the x values must correspond to one and only one y value.

In the coordinates given, (0.3, 0.6) and (0.3, 0.7) have the same x- value.

That means that they cannot be a function.

7 0
4 years ago
Can someone write 27/11 as a decimal for me please?
kicyunya [14]

Answer:0.4074

Step-by-step explanation:I used google

3 0
3 years ago
The product of two positive numbers is 48. the larger number is 13 more than the smaller. Find both numbers [Only an algebraic s
Valentin [98]

Answer:

Larger number:

16

Smaller number

3

Step-by-step explanation:

Larger number: 16

Smaller number: 3

Explanation:

Suppose the larger number is

a

and the smaller number is

b

.

You solve the following system of equations:

a⋅b=48

a−13=b

Since b is a −13, you can plug that into a⋅b=48, so...a⋅(a−13)=48

a 2−13a=48

a2−13a−48=0

Factor the polynomial:

(a−16)(a+3)=0

a=16 or a=−3a is positive so a=16.

We can now solve for b by plugging in a, so...16−13=b3=b We have a=16 and b=3, meaning that the larger number is 16 and the smaller number is 3.

5 0
3 years ago
In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.
Hitman42 [59]

\longmapstoThe value of "x" is 5.

\large\underline{\sf{Solution-}}

Given that,

A trapezium ABCD in which AB || CD such that

  • AO = x - 1

  • CO = BO = x + 1

  • OD = x + 4

Now,

\rm In \: \triangle  \: AOB  \: and \: \triangle \:  COD

\rm  \: \angle  \: AOB  \: and \: \angle \:  COD \:  \:  \{vertically \: opposite \: angles \}

\rm  \: \angle  \:ABO  \: and \: \angle \:  CDO \:  \:  \{alternate \: interior \: angles \}

\bf \: \triangle  \: AOB \:  \sim \:  \triangle  \: COD \:  \:  \:  \{AA \: similarity \}

\bf\longmapsto\:\dfrac{AO}{CO}  = \dfrac{BO}{DO}

\rm \longmapsto\:\dfrac{x - 1}{x + 1}  = \dfrac{x + 1}{x + 4}

\rm \longmapsto\:(x - 1)(x + 4) =  {(x + 1)}^{2}

\rm \longmapsto\: {x}^{2} - x + 4x - 4 =  {x}^{2} + 1 + 2x

\rm \longmapsto\: 3x - 4 =  1 + 2x

\rm \longmapsto\: 3x  -  2x=  1 +4

\bf\longmapsto \:x = 5

7 0
3 years ago
a certain drug is made from only two ingredients: compound A and comppund B. There are 5 milliliters of compound A used for ever
yaroslaw [1]
4:5 is the same as 4x:5x where 4x is compound A and 5x is compound B.
---
Solve for "x":
If amount of compound A is 4x = 477
x = 477/4
Then amt of compound B is 5x = 5(477/4) = 596.25 ml
7 0
3 years ago
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