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2 years ago

14

Diffrentiate between save and save as

2 answers:

Ainat [17]2 years ago

8 0

Step-by-step explanation:

The main difference between Save and Save As is that Save helps to update the lastly preserved file with the latest content while Save As helps to store a new file or to store an existing file to a new location with the same name or a different name.mark me brainlist if i help

maw [93]2 years ago

6 0

Answer:

difference between save and save as is that save helps to update lastly preserved file with least content while save as to store a new file or to store an existing file to a new location with the same name or different name.

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if a ball is rolling down hill and accelerating at a rate of 2m/s^2 because of a 2N net force. What is the mass of the ball?

Vedmedyk [2.9K]

Answer:

<h3>1kg</h3>

Step-by-step explanation:

According to Newton's second law

Force = mass * acceleration

Given

Force = 2N

acceleration = 2m/s^2

Mass =Force/Acceleration

Mass = 2/2

Mass =1kg

Hence the mass of the ball is 1kg

8 0

2 years ago

Need help ASAP !!!!<br> Solve for y

GarryVolchara [31]

Answer:

y=8.94

Step-by-step explanation:

use the formula: a^2+b^2=c^2

64+y^2=144

y= $\sqrt{80}$

or y=8.94

8 0

2 years ago

What is the approximate area of the triangle below ?

aleksandrvk [35]

Answer:

72.8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Giving right answer a branleist

Kobotan [32]

Answer:

(a) 860, (b) 860, (c) 860 and 186

Step-by-step explanation:

(a) 860

860 ends with a zero or a five, 186 and 863 do not.

(b) 860

860 ends with a zero, 186 and 863 do not.

(c) 860, 186

860, the 0 is even. 186, the 6 is even. 863, the 3 is not even.

7 0

2 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

2 years ago