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3 years ago

Y+4=2(x+5)

Mathematics

1 answer:

Ainat [17]3 years ago

6 0

Answer:

y= 2x+6

y= x+3

1 Is slope

3 is y intercept or the line that it passes through

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The base value is the A. New value B. Current value

Andrei [34K]

The base value is the current value

Good luck! I hope this helps!

6 0

3 years ago

Identify the data set that could be quadratic. HELP ASAP!!

Ne4ueva [31]

Answer:

Option B can be quadratic.

Step-by-step explanation:

Take a look at the data.

A quadratic equation is of the form ,

$y = ax^{2} +bx + c$ ,

where, a,b,c are constants.

To find an unknown equation of 3 variables,

we need 3 points lying on the equation.

here they have given, 5 points, meaning all should lie on the curve.

For first option, inserting first 3 points to find equation, we get equation as,

$y = x^{2} -4x +11$ , but the rest points don't satisfy the curve.

So first option is not quadratic.

Similarly, it can be shown that option C and D are also not quadratic.

While, in option B, it is clear that for every y, x is y squared,

$x = y^{2}$ , thus quadratic in nature.

6 0

3 years ago

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$

Therefore, the dimensions of the yard are W=20ft and L=40ft.

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2 years ago

A group of 10 men who were recently diagnosed with testicular cancer recently gathered to share their feelings and provide mutua

sveta [45]

5men because half of them would probably not make it

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2 years ago

The length of a rectangular field is 4 meters less than 5 times the breadth of the hall. What is the length, if the breadth is b

vlabodo [156]

IF BREADTH=b meters
THEN LENGTH=4 meter less than 3 times than the breadth of the hall.
LENGTH=3b-4 meters
the length of the rectangular hall is=3b-4 meters

4 0

2 years ago