Question

Two planes are 1380 miles apart and traveling toward each other. One plane is traveling

Answer 1

Answer: plane 1: 420 mph; plane 2: 500 mph

Step-by-step explanation:

This is a physics exercise, but in order to solve this problem, you need to identify both planes first:

Let's call the plane 1 speed X

V1 = X

And V2 would be:

V2 = V1 + 80 = X + 80

If we combine both speeds:

V = V1 + V2 = X + X + 80 = 2X + 80

Now that we have an expression for the combined speed, let's see the rest of the data:

Distance: d = 1380 mile

Time: t = 1.5 h

We also know that the formula to get speed is:

V = d/t

We have the combined speed, so, let replace it in the above formula to solve for X:

2X + 80 = 1380/1.5

2X + 80 = 920

2X = 920 - 80

2X = 840

X = 840/2

X = V1 = 420 mph

We have V1, so to get V2:

V2 = 420 + 80 = 500 mph