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3 years ago

Two planes are 1380 miles apart and traveling toward each other. One plane is traveling

Mathematics

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer: plane 1: 420 mph; plane 2: 500 mph

Step-by-step explanation:

This is a physics exercise, but in order to solve this problem, you need to identify both planes first:

Let's call the plane 1 speed X

V1 = X

And V2 would be:

V2 = V1 + 80 = X + 80

If we combine both speeds:

V = V1 + V2 = X + X + 80 = 2X + 80

Now that we have an expression for the combined speed, let's see the rest of the data:

Distance: d = 1380 mile

Time: t = 1.5 h

We also know that the formula to get speed is:

V = d/t

We have the combined speed, so, let replace it in the above formula to solve for X:

2X + 80 = 1380/1.5

2X + 80 = 920

2X = 920 - 80

2X = 840

X = 840/2

X = V1 = 420 mph

We have V1, so to get V2:

V2 = 420 + 80 = 500 mph

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3 years ago

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A web-based company has a goal of processing 95 percent of its orders on the same day they are received. If 485 out of the next

HACTEHA [7]

Answer:

The null hypothesis was rejected.

Conclusion: The proportions of orders completed on the day of receiving is more than 95%.

Step-by-step explanation:

The hypothesis can be defined as:

H₀: The proportions of orders completed on the day of receiving is not more than 95%, i.e. p ≤ 0.95.

Hₐ: The proportions of orders completed on the day of receiving is more than 95%, i.e. p > 0.95.

The significance level of the test is α = 0.025.

The sample size is, n = 500.

As the sample size is large, the sampling distribution of sample proportion can be approximated by the Normal distribution.

The mean and standard deviation of this distribution are:

$\mu=p\\\sigma=\sqrt{\frac{p(1-p)}{n}}$

The test statistic is:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{485}{500}=0.97$

Compute the test statistic as follows:

$z=\frac{0.97-0.95}{\sqrt{\frac{0.95(1-0.95)}{500}} }=2.05$

The decision rule is:

If the p-value is less than the significance level α then the null hypothesis is rejected.

Compute the p-value as follows:

$p-value=P(Z>2.05)\\=1-P(Z$

*Use a z-table.

The p-value = 0.0202 < α = 0.025.

The null hypothesis will be rejected.

Conclusion:

As the null hypothesis was rejected at 2.5% level of significance, it can be concluded that the proportions of orders completed on the day of receiving is more than 95%.

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3 years ago

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Answer:

It is an exponential function.

Initial value is - 1.8 and the base is 6.

Step-by-step explanation:

The function is given by $y = - 1.8 (6)^{x}$ and it is an exponential function as the general form of an exponential function is $y = a(b)^{x}$ .

Here, if we put x = 0, the function becomes $y = - 1.8 (6)^{0} = - 1.8$ .

Therefore, the initial value of the function is - 1.8.

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3 years ago

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aleksandrvk [35]

Answer:

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Step-by-step explanation:

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