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Liono4ka [1.6K]
2 years ago
7

This question has 2 parts.

Mathematics
1 answer:
Liula [17]2 years ago
3 0

Answer:

um well i can do part A

Step-by-step explanation:

its 6/24 which equals 1/4 yards

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Jay wants to buy 4 shirts which were originally priced at $15.95 each. He purchased the 4 shirts at a 20% off sale and pays a 6.
Murrr4er [49]

Answer:

I think its $32.50

Step-by-step explanation:

15.95 * 4 = 63.8

63.8 / 1/5 = 12.76

20% = 1/5

319 + 6 1/2 = 32.50

6 0
3 years ago
Please I BEG YOU! Find the ordered pair (x,y) if x+y=(5-x)+(5-y), x-y=(x-1)+(y-1).
qwelly [4]

Answer:

x=4, y=1

I think its that

Step-by-step explanation:

8 0
3 years ago
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Help on number 6 i don't understand how to do it and i got corrections so i need help to do them.
Mademuasel [1]
The answer #6 is j. 100. He uses the treadmill for 40% so that means 60% of his exercise is not on the treadmill. 

40%= 40 mins 
60%= 60 mins
 total: 100%= 100 mins.
Hope this helps!
8 0
3 years ago
Read 2 more answers
The base of a rectangular box has a width of 3 inches and a length of 4 inches. The box is 12 inches inches tall. a) Draw a pict
posledela
it would be 144 inches
8 0
3 years ago
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The heights (in inches) and pulse rates (in beats per minute) for a sample of 40 women were measured. Using technology with the
Viktor [21]

Answer:

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

Step-by-step explanation:

The correlation coefficient between the variables h(height in inches) and pulse rates (in beats per minute) is 0.202

Sample size n=40

Level of significane alpha = 0.01

Create null and alternate hypothesis as:

H0: r=0

Ha: r not equal 0

(Two tailed test at 1% significance level)

Sample r = 0.202

r difference = 0.202

test statistic t = \frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{0.202(\sqrt{38} )}{\sqrt{0.9592} } \\=\frac{1.25}{0.9794} \\=1.271

df =n-2 =38

t critical value for 0.01 and df =38 is 2.704

Since our test statistic lies below 2.704, we accept null hypothesis

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

7 0
3 years ago
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