This question has 2 parts.

Mathematics

1 answer:

Liula [17]2 years ago

3 0

Answer:

um well i can do part A

Step-by-step explanation:

its 6/24 which equals 1/4 yards

You might be interested in

Ax+by=(a-b) , bx - ay =(a+b) simultaneous linear equations using cross multiplication

Molodets [167]

Answer:

$x=1\,,\,y=-1$

Step-by-step explanation:

Given: $ax+by=a-b\,,\,bx-ay=a+b$

To solve: the given linear equations

Solution:

Consider the equations:

$A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0$

By method of cross multiplication:

$\frac{x}{B_1C_2-B_2C_1}=\frac{y}{C_1A_2-C_2A_1}=\frac{1}{A_1B_2-A_2B_1}$

For equations: $ax+by=a-b\,,\,bx-ay=a+b$

$ax+by-(a-b)=0\\bx-ay-(a+b)=0$

Take $A_1=a\,,\,B_1=b\,,\,C_1=-(a-b)\,,\,A_2=b\,,\,B_2=-a\,,\,C_2=-(a+b)$

So,

$\frac{x}{-b(a+b)-a(a-b)}=\frac{y}{-b(a-b)+a(a+b)}=\frac{1}{-a^2-b^2}\\\frac{x}{-ab-b^2-a^2+ab}=\frac{y}{-ab+b^2+a^2+ab}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{1}{-(a^2+b^2)}\,,\,\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\x=1\,,\,y=-1$

6 0

2 years ago

The figure below shows a rectangle ABCD having diagonals AC and DB: A rectangle ABCD is shown with diagonals AC and BD. Anastasi

erica [24]

Answer:In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent)

Step-by-step explanation:

As congruent means shapes having the same length and same internal angles. In the given figure the two statements are already written. The only information about sides AD and BC are missing to complete the proof of congruent diagonals.

7 0

2 years ago

Solve by substitution 4x+2y=10 x-y=13

Savatey [412]

4x+2y=10
x-y=13

x=13+y
4(13+y)+2y=10
52+4y+2y=10
52+6y=10
6y=-42
y=-7
x=13+y=13-7=6

8 0

2 years ago

Read 2 more answers

A trucker traveled an average of 48.6 miles each hour on a 583.2-mile trip. For how many hours did the trucker travel?

nexus9112 [7]

Divide 583.2 by 48.6 to get your answer, 12 hours.

5 0