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KonstantinChe [14]
3 years ago
8

Henry was thinking of a number. Henry halves the number and gets an answer of 32.5. Form an equation with

Mathematics
1 answer:
Kamila [148]3 years ago
7 0
Since his number halved is 32.5 all you have to do is multiply 32.5 by 2.

x=32.5(2)
x=65
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6/7 as a fraction divided by a whole of 12
ValentinkaMS [17]

Answer:

<u>(1/14)</u>

Step-by-step explanation:

(6/7)/(12)              <u>6/7 as a fraction divided by a whole of 12</u>

(6/7)/(12/1)

(6/7)*(1/12)

(1/7)*(1/2)

(1/14)

4 0
2 years ago
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Which of the following systems of linear inequalities is represented by the solution graphed below?
sattari [20]
Answer is A, y us smaller/equal to 2 and y is smaller/equal to X
5 0
3 years ago
Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
2 years ago
Which expression is equivalent to 54.5-6?​
pentagon [3]

Answer: 5-6•54

Hope this helps (:

3 0
3 years ago
a utility worker is 5.5 feet tall and is casting a shadow 4 feet long at the same time a nearby utility pole casts a shadow 20 f
Assoli18 [71]

So this is essentially a proportion problem. They want you to be able to recognize a relationship between the two. The easiest way to go about this is to draw a picture (I have included one). What you want to do is notice that you are given both shadow lengths. This is essentially going to be your first step to creating the proportion.


Understanding that we know the shadow lengths, we can turn these into a fraction such as so:


4ft/20ft.


Now that we know that, we need to look at are unknown. Our unknown is the height of the utility pole. We can solve this by substituting for X since we know the utility worker is 5.5 ft tall.


Your fraction for that would look like:


5.5ft/X


Make sure to always make your top to top match, such as since I put the utility worker's shadow on top, I need to put his height on top.

Now we can solve.

4ft/20ft =5.5ft/X


We need to cross multiply to get an equation we can work with. If we cross multiply, Your equation will look like:


4x = 110ft


This is a simple one step equation. Divide both sides by 4 to get your answer.

x= 27.5ft.

This means your Utility pole's height is 27.5ft.

6 0
3 years ago
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