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KonstantinChe [14]
3 years ago
8

Henry was thinking of a number. Henry halves the number and gets an answer of 32.5. Form an equation with

Mathematics
1 answer:
Kamila [148]3 years ago
7 0
Since his number halved is 32.5 all you have to do is multiply 32.5 by 2.

x=32.5(2)
x=65
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Factor completely 3x2 - 21.
VMariaS [17]
3x² - 21

Factor 3 from both terms:

3 (x² - 7)

To me, that's as far as you should need to go.  But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:

3 (x + √7) (x - √7)

Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
factor that too:

3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)

but to me, this would be nonsense.
6 0
3 years ago
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Which equation represents a line that is parallel to y = -2x – 5?
Alex17521 [72]
I think is 2x+y=-5 the answer
3 0
3 years ago
Am i right or wrong pls help
Leto [7]

Answer:

Your correct!

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3 years ago
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P= -24<br>q= 12<br>r= -6<br><br>a. (pxq):(q+r)<br>b. (pxr):(r-q)<br><br>what the answer?​
kolezko [41]

Step-by-step explanation:

a. ( p × q ) ( q + r )

= ( -24 × 12 ) ( 12 + -6 )

= 288 × 18

= 5184

b. ( p × r ) ( r - q )

= ( -24 × -6 ) ( -6 - 12 )

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5 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
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